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48x^2+100x+48=0
a = 48; b = 100; c = +48;
Δ = b2-4ac
Δ = 1002-4·48·48
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-28}{2*48}=\frac{-128}{96} =-1+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+28}{2*48}=\frac{-72}{96} =-3/4 $
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